48x^2-2x-35=0

Solution for 48x^2-2x-35=0 equation:

48x^2-2x-35=0

a = 48; b = -2; c = -35;
Δ = b2-4ac
Δ = -22-4·48·(-35)
Δ = 6724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6724}=82$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-82}{2*48}=\frac{-80}{96}
=-5/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+82}{2*48}=\frac{84}{96}
=7/8
$